Topic Details (Notes format)

How to Calculate the Cross Product in 3D Vectors

Subject: Mathematics

Book: Maths Mastery

For 3D vectors u20d7A=[a₁,a₂,a₃] and u20d7B=[b₁,b₂,b₃], their cross product u20d7A×u20d7B is [a₂b₃–a₃b₂, a₃b₁–a₁b₃, a₁b₂–a₂b₁]. This new vector is perpendicular to both u20d7A and u20d7B, with magnitude = |A||B|sin(θ). Cross products are fundamental in calculating torque, normal vectors for surfaces, or rotation axes in physics. For instance, with u20d7A=[1,2,3] and u20d7B=[4,5,6], u20d7A×u20d7B=[(2×6–3×5), (3×4–1×6), (1×5–2×4)]=[12–15, 12–6, 5–8]=[–3,6,–3]. Proficiency ensures advanced 3D geometry or mechanical tasks are handled with rigor and clarity.

Practice Questions

If 2x - 3 = 7, what is the value of x?

View Question

If a square has a perimeter of 64 cm, what is its area?

View Question

What is the value of x if 3x + 7 = 16?

View Question

If a person can type 45 words per minute, how many words can they type in 2 hours?

View Question

What is the square root of 0.25?

View Question

If sin(A) = 3/5 and cos(B) = 5/13, where A and B are acute angles, what is sin(A+B)?

View Question

What is the value of log₃(27)?

View Question

The base of a triangle is 10 cm and its height is 6 cm. What is its area?

View Question

A car travels 240 km in 4 hours. What is its average speed?

View Question

The probability of rolling a sum of 7 with two dice is:

View Question