Topic Details (Notes format)

How to Calculate the Cross Product in 3D Vectors

Subject: Mathematics

Book: Maths Mastery

For 3D vectors u20d7A=[a₁,a₂,a₃] and u20d7B=[b₁,b₂,b₃], their cross product u20d7A×u20d7B is [a₂b₃–a₃b₂, a₃b₁–a₁b₃, a₁b₂–a₂b₁]. This new vector is perpendicular to both u20d7A and u20d7B, with magnitude = |A||B|sin(θ). Cross products are fundamental in calculating torque, normal vectors for surfaces, or rotation axes in physics. For instance, with u20d7A=[1,2,3] and u20d7B=[4,5,6], u20d7A×u20d7B=[(2×6–3×5), (3×4–1×6), (1×5–2×4)]=[12–15, 12–6, 5–8]=[–3,6,–3]. Proficiency ensures advanced 3D geometry or mechanical tasks are handled with rigor and clarity.

Practice Questions

What is the square root of 0.25?

View Question

If the angles of a triangle are in the ratio 2:3:4, what is the measure of the largest angle?

View Question

A train 120 meters long is moving at a speed of 54 km/h. How long will it take to pass a pole?

View Question

What is the sum of the interior angles of a hexagon?

View Question

If x = 3 and y = 4, what is the value of x^2 + y^2?

View Question

If x^2 - 5x + 6 = 0, what are the roots?

View Question

A square is inscribed in a circle with a radius of 5 cm. What is the area of the square?

View Question

How many diagonals does a pentagon have?

View Question

If the probability of an event is 1/4, what is the probability of its complement?

View Question

If x² - 9x + 18 = 0, what are the roots of the equation?

View Question